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release time:2023-03-21
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The correct expression of the battery pack should be how much V, and the AH in which AH expresses amp .a is a current ampere .h is the hourly hour. It reflects the product of current and time. The method is that the voltage of the battery pack can be released for 10 hours or 10A current with a current of 1A or at a current of 1A or one hour. The standard for the battery life of electric vehicle battery is how to calculate it. Let's make a simple description below .. For example, the 48V10AH battery pack is used on the 350W motor. ... Here are several formulas .P = u*A among them. P is power, that is, 350W and U represents the voltage 48V A represents current.
From the previous formula, it can be inferred that the rated working current of 350W motors is about 7.3A. The 10AH battery pack can run about 10AH/7.3A = 1.37 hours. /H*1.37=41.1km. The above example. It is not difficult for all the theoretical values of all battery packs to overwhelm the theoretical value of all battery packs.
S stands for Miles H represents time A represents current V represents speed P represents the power. W represents the voltage of the voltage assumption of the rated power of the motor 350W; V assumes the constant average speed: 30km/h
S = V*H formula 1 high school physics; s = vt
H = A*H/A Formula 2
P = U*A Formula 3 High School Physics; P = UI
W = AH*U Formula 4 High School Physics: W = UIT
It is not difficult to see from Formula 4, such as 48V10AH reflected, that is, the power that can be done by the battery pack, that is, W, and time h = w/p; mileage s = v*w/p; The average speed of 30km/h on a battery pack at a rated power of 350W is easy to get out of the mileage.
S = 30km/h*48V*12AH/350W = 49.3km
S = 30km/h*60V*12AH/350W = 61.7km
S = 30km/h*48V*20AH/350W = 82.3km
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